Strain formula
(b) The lateral strain will be given by
`\ε_2` = `\frac(µσ_1) (E_2)`
E =`\frac(µσ₁) ε`
= 150 GPa
`\E_2`
`\sum_{i=1}^n T_i = T`
`\{matrix}\sigma_x&\tau_{xy}&\tau_{xz} \\\tau_{xy}&\sigma_y&\tau_{yz} \\\tau_{xz}&\tau_{yz}&\sigma_z\{matrix}`
`\int_{x_A}^{x_B}\frac{M(x)}{EI} dx`
`\1&2\\5&6`
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