Exercise 1.5 Solutions (เคช्เคฐเคถ्เคจाเคตเคฒी 1.5)
Q1: Find the value of:
(เค्เคाเคค เคीเคिเค:)
(i) 641/2
We know 64 = 8². So, (8²)1/2 = 82 × (1/2) = 8
(ii) 321/5
We know 32 = 25. So, (25)1/5 = 25 × (1/5) = 2
(iii) 1251/3
We know 125 = 53. So, (53)1/3 = 53 × (1/3) = 5
Q2: Find the value of:
(เค्เคाเคค เคीเคिเค:)
(i) 93/2
= (3²)3/2 = 32 × (3/2) = 33 = 27
(ii) 163/4
= (24)3/4 = 24 × (3/4) = 23 = 8
(iii) 125-1/3
= (53)-1/3 = 5-1 = 1/5
Q3: Simplify:
(เคธเคฐเคฒ เคीเคिเค:)
(i) 22/3 · 21/5
Bases are the same, so add exponents: 2/3 + 1/5 = (10 + 3)/15 = 13/15.
= 213/15
(ii) 111/2 / 111/4
Bases are the same in division, so subtract exponents: 1/2 - 1/4 = 1/4.
= 111/4
ch-2-index-here
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