Exercise 1.4 Solutions (рдк्рд░рд╢्рдиाрд╡рд▓ी 1.4)
Q1: Classify the following numbers as rational or irrational.
(рдмрддाрдЗрдП рдиीрдЪे рджी рдЧрдИ рд╕ंрдЦ्рдпाрдУं рдоें рдХौрди-рдХौрди рдкрд░िрдоेрдп рд╣ैं рдФрд░ рдХौрди-рдХौрди рдЕрдкрд░िрдоेрдп рд╣ैं।)
(i) 2 - √5 ⇒ Irrational (рдЕрдкрд░िрдоेрдп) - Because subtracting an irrational from a rational gives an irrational.
(ii) (3 + √23) - √23 ⇒ 3 + √23 - √23 = 3 ⇒ Rational (рдкрд░िрдоेрдп)
(iii) 2π ⇒ Irrational (рдЕрдкрд░िрдоेрдп) - Because π is irrational.
Q2: Simplify each of the following expressions.
(рдиिрдо्рдирд▓िрдЦिрдд рд╡्рдпंрдЬрдХों рдоें рд╕े рдк्рд░рдд्рдпेрдХ рдХो рд╕рд░рд▓ рдХीрдЬिрдП।)
(i) (3 + √3)(2 + √2)
= 3(2 + √2) + √3(2 + √2)
= 6 + 3√2 + 2√3 + √6
(ii) (5 + √5)(5 - √5)
Using formula (a+b)(a-b) = a² - b²
= (5)² - (√5)² = 25 - 5 = 20
Q5: Rationalize the denominators of the following.
(рдиिрдо्рдирд▓िрдЦिрдд рдХे рд╣рд░ों рдХा рдкрд░िрдоेрдпрдХрд░рдг рдХीрдЬिрдП।)
(i) 1 / √7
Multiply numerator and denominator by √7:
= (1 × √7) / (√7 × √7) = √7 / 7
(ii) 1 / (√7 - √6)
Multiply by the conjugate (√7 + √6):
= [1 × (√7 + √6)] / [(√7 - √6)(√7 + √6)]
= (√7 + √6) / (7 - 6) = √7 + √6
ex-1-5-url-here
ЁЯФН Search more MP Board Solutions
Academic Discussion & Doubts